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Applications of Forces

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Question 2

A particle is moving across a perfectly smooth horizontal surface at a constant velocity. It is acted upon by exactly two constant horizontal forces.

The first force is F1=(250i−120j) N\mathbf{F}_1 = (250\mathbf{i} - 120\mathbf{j})\text{ N}F1​=(250i−120j) N.

The second force is F2=(ki+120j) N\mathbf{F}_2 = (k\mathbf{i} + 120\mathbf{j})\text{ N}F2​=(ki+120j) N.

Find the value of kkk.

Select your answer from the following:

−250-250−250

−130-130−130

130130130

250250250

[4]

Applications of Forces Questions

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