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1.10 Vectors

1.10 Vectors

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Question 24

It is given that v=6i−2j+3k\mathbf{v} = 6\mathbf{i} - 2\mathbf{j} + 3\mathbf{k}v=6i−2j+3k.

a.

Find ∣v∣\left|\mathbf{v}\right|∣v∣.

[2]
b.

Find a unit vector in the direction of v\mathbf{v}v.

The vector w=ci−4j+6k\mathbf{w} = c\mathbf{i} - 4\mathbf{j} + 6\mathbf{k}w=ci−4j+6k is parallel to v\mathbf{v}v, where c c\,c is a constant.

[2]
c.

Find the value of c c\,c and the value of ∣w∣\left|\mathbf{w}\right|∣w∣.

[3]
Markscheme

1.10 Vectors Questions

  1. A Level
  2. /Maths
  3. /1.10 Vectors

197 exam-style questions on OCR A Level Maths 1.10 Vectors, covering 1.10.1 Vectors in two dimensions, 1.10.2 Vectors in three dimensions (A-level only), 1.10.3 Magnitude and direction of vectors, 1.10.4 Basic operations on vectors, 1.10.5 Position vectors, 1.10.6 Distance between points, 1.10.7 Problem solving using vectors, 1.10.8 Vectors in kinematics, and 1.10 Vectors. Each one has a worked solution and a mark scheme showing where the marks go.

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