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1.5 Trigonometry

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1
Question 1
a.

Show that the equation

3sin⁡2xtan⁡2x=cos⁡2x+2 3\sin 2x \tan 2x = \cos 2x + 2 3sin2xtan2x=cos2x+2

Can be written in the form

4cos⁡22x+2cos⁡2x−3=0 4\cos^2 2x + 2\cos 2x - 3 = 0 4cos22x+2cos2x−3=0
[4]
b.

Find all values for x x\,x in the interval 0≤x<180∘0 \leq x < 180^\circ0≤x<180∘, for which

3sin⁡2xtan⁡2x=cos⁡2x+2 3\sin 2x \tan 2x = \cos 2x + 2 3sin2xtan2x=cos2x+2

Give your answers to two decimal places.

[6]

1.5 Trigonometry Questions

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