Given that P(X)=xP(X) = xP(X)=x and P(Y)=yP(Y) = yP(Y)=y, express P(X∪Y)P(X \cup Y)P(X∪Y) in terms of xxx and yyy when: (i) XXX and YYY are mutually exclusive, (ii) XXX and YYY are independent.
Two events CCC and DDD are such that
P(C∩D′)=0.25,P(D)=0.40andP(C∣D)=0.2 P(C \cap D') = 0.25, \quad P(D) = 0.40 \quad \text{and} \quad P(C|D) = 0.2 P(C∩D′)=0.25,P(D)=0.40andP(C∣D)=0.2Find the value of: P(C∪D)P(C \cup D)P(C∪D)
P(C∩D)P(C \cap D)P(C∩D)
P(C)P(C)P(C)
200 exam-style questions on OCR (MEI) A Level Maths 2.3 Probability, covering 2.3.1 Calculate the probability of an event, 2.3.2 Complementary events, 2.3.3 Expected frequency of an event, 2.3.4 Diagrams to calculate probabilities, 2.3.5 Mutually exclusive and independent events, 2.3.6 Add probabilities for mutually exclusive events, 2.3.7 Multiply probabilities for independent events, 2.3.8 Mutually exclusive and independent events (notation) (A-level only), 2.3.9 Venn diagrams for probabilities (A-level only), 2.3.10 Conditional probabilities (A-level only), and 2.3.11 Independence via conditional probability (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.