The concentration CCC (in mg/L) of a metabolic byproduct in a bioreactor is monitored over a 2-hour period. The rate of change of concentration is modeled by the function C(t)=81+2tC(t) = \frac{8}{\sqrt{1 + 2^t}}C(t)=1+2t8 for 0≤t≤20 \le t \le 20≤t≤2, where ttt is measured in hours.
A researcher uses the trapezium rule with 5 ordinates (4 strips) to find an approximation for the total exposure (the area under the curve) over this interval. The values required for this approximation are shown in the table below.
| ttt | 0 | 0.5 | 1 | 1.5 | 2 |
|---|---|---|---|---|---|
| CCC | 5.65685 | 5.14875 | 4.61880 | 4.08865 | 3.57771 |
Use the trapezium rule with all 5 ordinates from the table to find an approximate value for the total exposure over the interval 0≤t≤20 \le t \le 20≤t≤2. Give your answer to four decimal places.
Using your answer to part (a), deduce an estimate for ∫02241+2t dt\int_{0}^{2} \frac{24}{\sqrt{1 + 2^t}} \, dt∫021+2t24dt.
137 exam-style questions on OCR (MEI) A Level Maths 1.10 Numerical Methods (A-level only), covering 1.10.1 Locate roots by change of sign (A-level only), 1.10.2 When change of sign methods fail (A-level only), 1.10.3 Fixed point iteration (A-level only), 1.10.4 Newton-Raphson method (A-level only), 1.10.5 Convergence of iterations (A-level only), 1.10.6 Trapezium rule (A-level only), 1.10.7 Upper and lower bounds using rectangles (A-level only), and 1.10.8 Numerical methods to solve problems (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.