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3 Mechanics

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Question 89

A tracking carriage moves along a straight rail with acceleration a=(6t−12) m s−2a=(6t-12)\text{ m s}^{-2}a=(6t−12) m s−2. At t=0t=0t=0 it is at the origin and has velocity u m s−1u\text{ m s}^{-1}u m s−1. The carriage returns to the origin at t=4t=4t=4 s.

a.

Find uuu.

[3]
b.

Find the total distance travelled by the carriage in the first 4 s. Give your answer in exact form.

[4]
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3 Mechanics Questions

  1. A Level
  2. /Maths
  3. /3 Mechanics

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