Using the substitution u=3x+1u = \sqrt{3x+1}u=3x+1, show that
∫1512x+4e3x+1 dx \int_{1}^{5} \sqrt{12x+4} e^{\sqrt{3x+1}} \, dx ∫1512x+4e3x+1dxmay be expressed in the form
∫abku2eu du \int_{a}^{b} k u^2 e^u \, du ∫abku2euduwhere aaa, bbb and kkk are constants to be found.
Hence find, by algebraic integration, the exact value of
∫1512x+4e3x+1 dx \int_{1}^{5} \sqrt{12x+4} e^{\sqrt{3x+1}} \, dx ∫1512x+4e3x+1dxgiving your answer in simplest form.