The rate of mass accumulation in a sediment trap is modeled by the function R(t)=12t4t+1R(t) = \dfrac{12t}{\sqrt{4t+1}}R(t)=4t+112t, where R R\,R is the rate in grams per day and t t\,t is the time in days since the start of the study. Using a suitable substitution, find the exact mass accumulated during the first 2 days.
Find ∫6x2−12x−26(x−4)(2x+3) dx\int \dfrac{6x^2 - 12x - 26}{(x - 4)(2x + 3)} \, dx∫(x−4)(2x+3)6x2−12x−26dx
