Use the substitution u=1+cosxu = 1 + \cos xu=1+cosx to find ∫0π2sinx1+cosxdx\displaystyle \int_0^{\frac{\pi}{2}} \frac{\sin x}{1 + \cos x} dx∫02π1+cosxsinxdx
59 exam-style questions on OCR (MEI) A Level Maths 1.9.28 Integration by substitution (other cases) (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.