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1.9.28 Integration by substitution (other cases) (A-level only)

1.9.28 Integration by substitution (other cases) (A-level only)

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Question 10

Use the substitution u=x3−1u = x^3 - 1u=x3−1 to find ∫134x2(x3−1)2dx\int_1^3 4x^2(x^3 - 1)^2 dx∫13​4x2(x3−1)2dx.

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Markscheme

1.9.28 Integration by substitution (other cases) (A-level only) Questions

  1. A Level
  2. /Maths
  3. /1.9.28 Integration by substitution (other cases) (A-level only)

59 exam-style questions on OCR (MEI) A Level Maths 1.9.28 Integration by substitution (other cases) (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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