In this question use g=9.8g = 9.8g=9.8 m s−2^{-2}−2.
A particle of mass 6 kg is held in equilibrium by a light string and a horizontal force. The string slopes upwards to the left at 40∘ 40^\circ\,40∘ above the horizontal and has tension T T\,T N. The horizontal force has magnitude F F\,F N and acts to the right.
Find T T\,T and FFF.
State the resultant of the tension and the horizontal force.