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3 Mechanics

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Question 130

The resultant of forces F1=(2pi−4qj) N\mathbf{F}_1=(2p\mathbf{i}-4q\mathbf{j})\text{ N}F1​=(2pi−4qj) N and F2=(3qi+4pj) N\mathbf{F}_2=(3q\mathbf{i}+4p\mathbf{j})\text{ N}F2​=(3qi+4pj) N is (i−14j) N(\mathbf{i}-14\mathbf{j})\text{ N}(i−14j) N.

Determine p p\,p and qqq.

[5]
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3 Mechanics Questions

  1. A Level
  2. /Maths
  3. /3 Mechanics

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