A curve has the parametric equations
x=ln(t+1),y=t2−5,t>−1 x = \ln(t + 1), \quad y = t^2 - 5, \quad t > -1 x=ln(t+1),y=t2−5,t>−1Find the points where the curve crosses the coordinate axes.
Find an equation for the tangent to the curve when t=3t = 3t=3.
