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Trigonometric Functions

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Question 1
65%
a.

Use the identity cos⁡2θ+sin⁡2θ=1\cos^2\theta + \sin^2\theta = 1cos2θ+sin2θ=1 to prove that tan⁡2θ=sec⁡2θ−1\tan^2\theta = \sec^2\theta - 1tan2θ=sec2θ−1

[2]
b.

Solve, for 0≤θ≤3600 \leq \theta \leq 3600≤θ≤360, the equation,

tan⁡2θ+sec⁡2θ+5sec⁡θ=2 \tan^2\theta + \sec^2\theta + 5\sec\theta = 2 tan2θ+sec2θ+5secθ=2

Give your answers to 1 decimal place.

[5]

Trigonometric Functions Questions

  1. A Level
  2. /Maths
  3. /Trigonometric Functions