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Sequences and Series

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Question 51

An arithmetic progression has first term a a\,a and common difference bbb.

Prove that the sum of the first N N\,N terms of the progression is

SN=12N{2a+(N−1)b} S_N = \frac{1}{2}N\{2a + (N-1)b\} SN​=21​N{2a+(N−1)b}
[4]

Sequences and Series Questions

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