The equation x2+(n+1)x+(3−3n)=0x^2 + (n + 1)x + (3 - 3n) = 0x2+(n+1)x+(3−3n)=0, where n n\,n is a constant.
Given that
n<−7−215orn>−7+215, n < -7 - 2\sqrt{15} \quad \text{or} \quad n > -7 + 2\sqrt{15}, n<−7−215orn>−7+215,show that the equation has two distinct real roots.
322 exam-style questions on Edexcel A Level Maths Quadratics, covering 2.1 Solving Quadratics, 2.2 Completing the Square, 2.3 Sketching Quadratic Graphs, 2.4 The Discriminant, and 2.5 Modelling with Quadratics. Each one has a worked solution and a mark scheme showing where the marks go.