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Quadratics

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Question 57

The equation x2+4x+(k+1)(k+4)=0x^2 + 4x + (k + 1)(k + 4) = 0x2+4x+(k+1)(k+4)=0, where k k\,k is a constant has two distinct real solutions for xxx.

a.

Show that the discriminant of the equation is −4k(k+5)-4k(k+5)−4k(k+5).

[2]
b.

Hence find the set of possible values for kkk.

[3]
Markscheme

Quadratics Questions

  1. A Level
  2. /Maths
  3. /Quadratics

322 exam-style questions on Edexcel A Level Maths Quadratics, covering 2.1 Solving Quadratics, 2.2 Completing the Square, 2.3 Sketching Quadratic Graphs, 2.4 The Discriminant, and 2.5 Modelling with Quadratics. Each one has a worked solution and a mark scheme showing where the marks go.

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