The equation x2+(n+1)x+(a+bn)=0x^2 + (n + 1)x + (a + bn) = 0x2+(n+1)x+(a+bn)=0, where a a\,a and b b\,b are constants, has two distinct real roots precisely when n<−7−215n<-7-2\sqrt{15}n<−7−215 or n>−7+215n>-7+2\sqrt{15}n>−7+215.
Find the values of a a\,a and bbb.
49 exam-style questions on Edexcel A Level Maths 2.4 The Discriminant. Each one has a worked solution and a mark scheme showing where the marks go.