The equation x2+(2k−3)x+(k+3)=0x^2 + (2k - 3)x + (k + 3) = 0x2+(2k−3)x+(k+3)=0, where k k\,k is a constant, has no real roots for the values of k k\,k satisfying
4−192<k<4+192. \frac{4-\sqrt{19}}{2}<k<\frac{4+\sqrt{19}}{2}. 24−19<k<24+19.Verify this result.
49 exam-style questions on Edexcel A Level Maths 2.4 The Discriminant. Each one has a worked solution and a mark scheme showing where the marks go.