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2x3−73x2=23x−73x−2 \frac{2x^3-7}{3x^2}=\frac{2}{3}x-\frac{7}{3}x^{-2} 3x22x3−7=32x−37x−2Hence find ∫(2x3−73x2)dx\displaystyle \int \left( \frac{2x^3-7}{3x^2} \right) dx∫(3x22x3−7)dx writing your answer in its simplest form.
411 exam-style questions on Edexcel A Level Maths Integration, covering 13.1 Integrating x^n, 13.2 Indefinite Integrals, 13.3 Finding Functions, 13.4 Definite Integrals, 13.5 Areas under Curves, 13.6 Areas under the x-axis, and 13.7 Areas between curves and lines. Each one has a worked solution and a mark scheme showing where the marks go.