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∫k16(6x)dx=48−12k \int_k^{16} \left( \frac{6}{\sqrt{x}} \right) dx = 48-12\sqrt{k} ∫k16(x6)dx=48−12kHence find the value of k k\,k such that ∫k16(6x)dx=12\displaystyle \int_k^{16} \left( \frac{6}{\sqrt{x}} \right) dx = 12∫k16(x6)dx=12
411 exam-style questions on Edexcel A Level Maths Integration, covering 13.1 Integrating x^n, 13.2 Indefinite Integrals, 13.3 Finding Functions, 13.4 Definite Integrals, 13.5 Areas under Curves, 13.6 Areas under the x-axis, and 13.7 Areas between curves and lines. Each one has a worked solution and a mark scheme showing where the marks go.