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10.4 Solving Trigonometric Equations

10.4 Solving Trigonometric Equations

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Question 7
a.

Show that the equation

6cos⁡2x=4−sin⁡x 6\cos^2 x = 4 - \sin x 6cos2x=4−sinx

can be written in the form

6sin⁡2x−sin⁡x−2=0 6\sin^2 x - \sin x - 2 = 0 6sin2x−sinx−2=0
[3]
b.

Hence solve, for 0≤x<360∘0 \leq x < 360^\circ0≤x<360∘, the equation

6cos⁡2x=4−sin⁡x 6\cos^2 x = 4 - \sin x 6cos2x=4−sinx

Give your answers to one decimal place where appropriate.

[6]
Markscheme

10.4 Solving Trigonometric Equations Questions

  1. A Level
  2. /Maths
  3. /10.4 Solving Trigonometric Equations

11 exam-style questions on Edexcel A Level Maths 10.4 Solving Trigonometric Equations. Each one has a worked solution and a mark scheme showing where the marks go.

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