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10.4 Solving Trigonometric Equations

10.4 Solving Trigonometric Equations

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Question 11
a.

Show that the equation

3sin⁡2xtan⁡2x=cos⁡2x+2 3\sin 2x\tan 2x=\cos 2x+2 3sin2xtan2x=cos2x+2

can be written in the form

4cos⁡22x+2cos⁡2x−3=0. 4\cos^2 2x+2\cos 2x-3=0. 4cos22x+2cos2x−3=0.
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b.

Find all values of x x\,x in the interval 0≤x<180∘ 0\leq x<180^\circ\,0≤x<180∘ for which

3sin⁡2xtan⁡2x=cos⁡2x+2. 3\sin 2x\tan 2x=\cos 2x+2. 3sin2xtan2x=cos2x+2.

Give your answers to two decimal places.

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Markscheme

10.4 Solving Trigonometric Equations Questions

  1. A Level
  2. /Maths
  3. /10.4 Solving Trigonometric Equations

11 exam-style questions on Edexcel A Level Maths 10.4 Solving Trigonometric Equations. Each one has a worked solution and a mark scheme showing where the marks go.

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