The acceleration of a particle after t t\,t seconds is given by (2t−8) ms−2(2t - 8) \text{ ms}^{-2}(2t−8) ms−2. Given the velocity (vvv) of the particle is 12 ms-1 when t=0t = 0t=0.
Find v v\,v in terms of ttt.
Show that the particle is instantaneously at rest when t=2t = 2t=2 and when t=6t = 6t=6.
Hence find the distance between the two points the particle is instantaneously at rest.
308 exam-style questions on Edexcel A Level Maths Variable Acceleration, covering 11.1 Functions of Time, 11.2 Using Differentiation, 11.3 Maxima and Minima Problems, 11.4 Using Integration, and 11.5 Constant Acceleration Formulae. Each one has a worked solution and a mark scheme showing where the marks go.