A particle P P\,P moves in a straight line so that, at time t t\,t seconds, its acceleration a m s−2a \text{ m s}^{-2}a m s−2 is given by
a={10t−t20≤t≤9729t2t>9 a = \begin{cases} 10t - t^2 & 0 \leq t \leq 9 \\ \frac{729}{t^2} & t > 9 \end{cases} a={10t−t2t27290≤t≤9t>9At t=0t = 0t=0, P P\,P is at rest. Find the speed of P P\,P when
t=9t = 9t=9
t=18t = 18t=18
308 exam-style questions on Edexcel A Level Maths Variable Acceleration, covering 11.1 Functions of Time, 11.2 Using Differentiation, 11.3 Maxima and Minima Problems, 11.4 Using Integration, and 11.5 Constant Acceleration Formulae. Each one has a worked solution and a mark scheme showing where the marks go.