Skip to content

Course home

9.9 Using Second Derivatives

9.9 Using Second Derivatives

EasyMediumHard
12345678910111213141516171819202122232425262728293031323334353637383940414243444546
Question 11

The velocity, vvv m s−1\text{m s}^{-1}m s−1, of a research drone at time ttt seconds (t>0t > 0t>0) is defined such that its acceleration aaa follows the equation:

a=dvdt=12t+kt3+10 a = \frac{dv}{dt} = \frac{12}{\sqrt{t}} + \frac{k}{t^3} + 10 a=dtdv​=t​12​+t3k​+10

where kkk is a constant.

It is observed that the rate of change of the drone's acceleration is zero at the instant where t=4t = 4t=4.

a.

Determine the value of kkk.

[4]
b.

Given that the drone's velocity is 100100100 m s−1\text{m s}^{-1}m s−1 when t=1t = 1t=1, find an expression for vvv in terms of ttt, giving each term in simplest form.

[4]
Markscheme

9.9 Using Second Derivatives Questions

  1. A Level
  2. /Maths
  3. /9.9 Using Second Derivatives

57 exam-style questions on Edexcel A Level Maths 9.9 Using Second Derivatives. Each one has a worked solution and a mark scheme showing where the marks go.

Question bank