A curve has equation
y=2x3−3x2−12x+7 y = 2x^3 - 3x^2 - 12x + 7 y=2x3−3x2−12x+7Using calculus, find the xxx-coordinates of the stationary points of the curve.
Justify, by further calculus, the nature of each stationary point.
57 exam-style questions on Edexcel A Level Maths 9.9 Using Second Derivatives. Each one has a worked solution and a mark scheme showing where the marks go.