A curve has equation
y2=ye3x+2x y^2 = y e^{3x} + 2x y2=ye3x+2xShow that
dydx=3ye3x+22y−e3x \frac{dy}{dx} = \frac{3y e^{3x} + 2}{2y - e^{3x}} dxdy=2y−e3x3ye3x+2The curve crosses the yyy-axis at the origin (0,0)(0, 0)(0,0) and at a second point PPP. The tangent to the curve at the origin and the tangent to the curve at PPP meet at the point RRR. Find the coordinates of RRR.
47 exam-style questions on Edexcel A Level Maths 9.8 Implicit Differentiation. Each one has a worked solution and a mark scheme showing where the marks go.