A curve CCC has equation
y=xcosxx>0,y>0 y = x^{\cos x} \quad x > 0, \quad y > 0 y=xcosxx>0,y>0Find, by firstly taking natural logarithms, an expression for dydx\frac{dy}{dx}dxdy in terms of xxx and yyy.
Hence show that the xxx-coordinates of the stationary points of CCC are solutions of the equation
sin(x)⋅xlnx=cosx \sin(x) \cdot x \ln x = \cos x sin(x)⋅xlnx=cosx47 exam-style questions on Edexcel A Level Maths 9.8 Implicit Differentiation. Each one has a worked solution and a mark scheme showing where the marks go.