Course home

9.2 Differentiating exponentials and logarithms

Question 2

A specialized coolant's temperature, $θ\theta$ degrees Celsius, in a high-performance engine is modeled by the equation

\theta = 225e^{-0.04t}

where $t$ is the time in minutes since the engine was deactivated.

Determine an expression for the rate of change of the temperature, $dθdt\frac{d\theta}{dt}$ , in $min−1^{\circ}\text{C min}^{-1}$ .

Select the correct answer from the options below:

$dθdt=−9e−0.04t\frac{d\theta}{dt} = -9e^{-0.04t}$

$dθdt=9e−0.04t\frac{d\theta}{dt} = 9e^{-0.04t}$

$dθdt=−5625e−0.04t\frac{d\theta}{dt} = -5625e^{-0.04t}$

$dθdt=−0.04e−0.04t\frac{d\theta}{dt} = -0.04e^{-0.04t}$

[3]

Markscheme

9.2 Differentiating exponentials and logarithms Questions

A Level
Maths
9.2 Differentiating exponentials and logarithms

23 exam-style questions on Edexcel A Level Maths 9.2 Differentiating exponentials and logarithms. Each one has a worked solution and a mark scheme showing where the marks go.

9.2 Differentiating exponentials and logarithms

Question bank

9.2 Differentiating exponentials and logarithms

Easy Medium

1 2 3 4 5 6 7 8 9

Question 2

A specialized coolant's temperature, $θ\theta$ degrees Celsius, in a high-performance engine is modeled by the equation

\theta = 225e^{-0.04t}

where $t$ is the time in minutes since the engine was deactivated.

Determine an expression for the rate of change of the temperature, $dθdt\frac{d\theta}{dt}$ , in $min−1^{\circ}\text{C min}^{-1}$ .

Select the correct answer from the options below:

$dθdt=−9e−0.04t\frac{d\theta}{dt} = -9e^{-0.04t}$

$dθdt=9e−0.04t\frac{d\theta}{dt} = 9e^{-0.04t}$

$dθdt=−5625e−0.04t\frac{d\theta}{dt} = -5625e^{-0.04t}$

$dθdt=−0.04e−0.04t\frac{d\theta}{dt} = -0.04e^{-0.04t}$

[3]

Markscheme

9.2 Differentiating exponentials and logarithms Questions

A Level
Maths
9.2 Differentiating exponentials and logarithms

23 exam-style questions on Edexcel A Level Maths 9.2 Differentiating exponentials and logarithms. Each one has a worked solution and a mark scheme showing where the marks go.