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9.2 Differentiating exponentials and logarithms

Question 9

The signal strength, $S$ milliwatts, of a deep-space communications beam as it penetrates a nebulous gas cloud of density $ρ\rho$ kg m $^{-3}$ is modeled by the equation

240e^{-0.075\rho}

Determine an expression for the rate of change of signal strength with respect to density, $dSdρ\frac{dS}{d\rho}$ .

Select the correct answer from the options below:

$dSdρ=−180e−0.075ρ\frac{dS}{d\rho} = -180e^{-0.075\rho}$

$dSdρ=−18e−0.075ρ\frac{dS}{d\rho} = -18e^{-0.075\rho}$

$dSdρ=18e−0.075ρ\frac{dS}{d\rho} = 18e^{-0.075\rho}$

$dSdρ=−3200e−0.075ρ\frac{dS}{d\rho} = -3200e^{-0.075\rho}$

[2]

Markscheme

9.2 Differentiating exponentials and logarithms Questions

A Level
Maths
9.2 Differentiating exponentials and logarithms

23 exam-style questions on Edexcel A Level Maths 9.2 Differentiating exponentials and logarithms. Each one has a worked solution and a mark scheme showing where the marks go.

9.2 Differentiating exponentials and logarithms

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9.2 Differentiating exponentials and logarithms

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Question 9

The signal strength, $S$ milliwatts, of a deep-space communications beam as it penetrates a nebulous gas cloud of density $ρ\rho$ kg m $^{-3}$ is modeled by the equation

240e^{-0.075\rho}

Determine an expression for the rate of change of signal strength with respect to density, $dSdρ\frac{dS}{d\rho}$ .

Select the correct answer from the options below:

$dSdρ=−180e−0.075ρ\frac{dS}{d\rho} = -180e^{-0.075\rho}$

$dSdρ=−18e−0.075ρ\frac{dS}{d\rho} = -18e^{-0.075\rho}$

$dSdρ=18e−0.075ρ\frac{dS}{d\rho} = 18e^{-0.075\rho}$

$dSdρ=−3200e−0.075ρ\frac{dS}{d\rho} = -3200e^{-0.075\rho}$

[2]

Markscheme

9.2 Differentiating exponentials and logarithms Questions

A Level
Maths
9.2 Differentiating exponentials and logarithms

23 exam-style questions on Edexcel A Level Maths 9.2 Differentiating exponentials and logarithms. Each one has a worked solution and a mark scheme showing where the marks go.