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Trigonometry and Modelling

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Question 2
a.

Show that

2sin⁡3θ≡6sin⁡θ−8sin⁡3θ 2\sin 3\theta \equiv 6 \sin \theta - 8 \sin^3 \theta 2sin3θ≡6sinθ−8sin3θ
[4]
b.

Hence, solve, for 0≤θ<π0 \leq \theta < \pi0≤θ<π,

8sin⁡3θ−6sin⁡θ+2=0 8 \sin^3 \theta - 6 \sin \theta + 2 = 0 8sin3θ−6sinθ+2=0
[5]
Markscheme

Trigonometry and Modelling Questions

  1. A Level
  2. /Maths
  3. /Trigonometry and Modelling

348 exam-style questions on Edexcel A Level Maths Trigonometry and Modelling, covering 7.1 Addition Formulae, 7.2 Double Angle Formulae, 7.3 Solving Trigonometric Equations, 7.4 Simplifying a cos x +- b sin x, 7.5 Proving Trigonometric Identities, and 7.6 Modelling with Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.

Question bank