By writing sin3θ \sin 3\theta\,sin3θ as sin(2θ+θ)\sin(2\theta + \theta)sin(2θ+θ), show that sin3θ=3sinθ−4sin3θ\sin 3\theta = 3\sin\theta - 4\sin^3\thetasin3θ=3sinθ−4sin3θ
Solve, for 0≤θ≤π0 \leq \theta \leq \pi0≤θ≤π, the equation,
3sinθ−4sin3θ=0.5 3\sin\theta - 4\sin^3\theta = 0.5 3sinθ−4sin3θ=0.5Give your answers in terms of π\piπ.
Practise Edexcel A Level Maths 7.2 Double Angle Formulae with exam-style questions for A Level Maths. 24 questions, matched to the Edexcel A Level Maths (9MA0) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.