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7.2 Double Angle Formulae

7.2 Double Angle Formulae

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Question 5
a.

By writing sin⁡3θ \sin 3\theta\,sin3θ as sin⁡(2θ+θ)\sin(2\theta + \theta)sin(2θ+θ) show that sin⁡3θ=3sin⁡θ−4sin⁡3θ\sin 3\theta = 3\sin\theta - 4\sin^3\thetasin3θ=3sinθ−4sin3θ

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b.

Solve, for 0≤θ≤1800 \leq \theta \leq 1800≤θ≤180, the equation,

3sin⁡θ−4sin⁡3θ=0.4 3\sin\theta - 4\sin^3\theta = 0.4 3sinθ−4sin3θ=0.4

Give your answers to 1 decimal place.

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Markscheme

7.2 Double Angle Formulae Questions

  1. A Level
  2. /Maths
  3. /7.2 Double Angle Formulae

24 exam-style questions on Edexcel A Level Maths 7.2 Double Angle Formulae. Each one has a worked solution and a mark scheme showing where the marks go.

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