The population of a bacteria colony, PnP_nPn (in thousands), at the start of day nnn is modelled by the recurrence relation
Pn+1=A−BPn P_{n+1} = A - B P_n Pn+1=A−BPn P1=6 P_1 = 6 P1=6where AAA and BBB are constants.
Find, in terms of AAA and BBB, (i) P2P_2P2 (ii) P3P_3P3
Given that
Show that 2B2−5B−14=02B^2 - 5B - 14 = 02B2−5B−14=0.
Hence find the smaller possible value of P2P_2P2.
35 exam-style questions on Edexcel A Level Maths 3.7 Recurrence Relations. Each one has a worked solution and a mark scheme showing where the marks go.