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3.7 Recurrence Relations

3.7 Recurrence Relations

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Question 24

A sequence a1,a2,a3,…a_1, a_2, a_3, \dotsa1​,a2​,a3​,… is defined by

an+1=6−an a_{n+1} = 6 - a_nan+1​=6−an​

where a1=2a_1 = 2a1​=2.

Find the value of

a.

(i) a2a_2a2​

(ii) a85a_{85}a85​

[3]
b.

∑n=1100(3an+2)\sum_{n=1}^{100} (3a_n + 2)∑n=1100​(3an​+2)

[3]
Markscheme

3.7 Recurrence Relations Questions

  1. A Level
  2. /Maths
  3. /3.7 Recurrence Relations

35 exam-style questions on Edexcel A Level Maths 3.7 Recurrence Relations. Each one has a worked solution and a mark scheme showing where the marks go.

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