The rate of power consumption, P(t)P(t)P(t) in kilowatts, of an industrial cooling system is modeled by the function
P(t)=18t+45e2t+5 P(t) = \sqrt{18t+45} e^{\sqrt{2t+5}} P(t)=18t+45e2t+5where t≥0t \ge 0t≥0 is the time in hours since the start of the shift.
By using the substitution u=2t+5u = \sqrt{2t+5}u=2t+5, show that the total energy consumed in the interval 2≤t≤102 \le t \le 102≤t≤10, given by ∫210P(t) dt\int_{2}^{10} P(t) \, dt∫210P(t)dt, can be expressed in the form
∫abku2eu du \int_{a}^{b} k u^2 e^u \, du ∫abku2euduwhere aaa, bbb and kkk are integers to be found.
Hence find, by algebraic integration, the exact value of the total energy consumed between t=2t = 2t=2 and t=10t = 10t=10, giving your answer in the form pe5+qe3p e^5 + q e^3pe5+qe3 where ppp and qqq are integers.
864 exam-style questions on Edexcel A Level Maths Integration, covering 11.1 Integrating Standard Functions, 11.2 Integrating f(ax + b), 11.3 Using Trigonometric Identities, 11.4 Reverse Chain Rule, 11.5 Integration by Substitution, 11.6 Integration by Parts, 11.7 Partial Fractions, 11.8 Finding Areas, 11.9 The Trapezium Rule, 11.10 Solving Differential Equations, and 11.11 Modelling with Differential Equations. Each one has a worked solution and a mark scheme showing where the marks go.