1.1 Proof by Contradiction
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a.

Expand and simplify (p+3q)2(p + 3q)^2(p+3q)2.

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b.

An electronics engineer claims that for any non-zero voltage ratio vvv, the expression v+9vv + \frac{9}{v}v+v9​ is always greater than or equal to 6.

The engineer tests two values: When v=9v = 9v=9, 9+99=10≥69 + \frac{9}{9} = 10 \ge 69+99​=10≥6. When v=3v = 3v=3, 3+93=6≥63 + \frac{9}{3} = 6 \ge 63+39​=6≥6.

Provide a counter-example to show that the engineer's claim is incorrect.

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c.

Given that xxx and yyy are positive real numbers such that x≠3yx \neq 3yx=3y, use proof by contradiction to prove that: xy+9yx>6\frac{x}{y} + \frac{9y}{x} > 6yx​+x9y​>6

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1.1 Proof by Contradiction Questions

Practise Edexcel A Level Maths 1.1 Proof by Contradiction with exam-style questions for A Level Maths. 100 questions, matched to the Edexcel A Level Maths (9MA0) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.

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1.1 Proof by Contradiction Questions

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