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1.1 Proof by Contradiction

1.1 Proof by Contradiction

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Question 70
a.

Expand and simplify (p+3q)2(p + 3q)^2(p+3q)2.

[1]
b.

An electronics engineer claims that for any non-zero voltage ratio vvv, the expression v+9vv + \frac{9}{v}v+v9​ is always greater than or equal to 6.

The engineer tests two values: When v=9v = 9v=9, 9+99=10≥69 + \frac{9}{9} = 10 \ge 69+99​=10≥6. When v=3v = 3v=3, 3+93=6≥63 + \frac{9}{3} = 6 \ge 63+39​=6≥6.

Provide a counter-example to show that the engineer's claim is incorrect.

[1]
c.

Given that xxx and yyy are positive real numbers such that x≠3yx \neq 3yx=3y, use proof by contradiction to prove that:

xy+9yx>6 \frac{x}{y} + \frac{9y}{x} > 6 yx​+x9y​>6
[4]
Markscheme

1.1 Proof by Contradiction Questions

  1. A Level
  2. /Maths
  3. /1.1 Proof by Contradiction

107 exam-style questions on Edexcel A Level Maths 1.1 Proof by Contradiction. Each one has a worked solution and a mark scheme showing where the marks go.

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