A particle $P\,$ is projected from a point $O\,$ with velocity $Ums−1U\text{ms}^{-1}$ at an angle of $\theta^\circ\,$ to the horizontal. When $P\,$ has moved a horizontal distance $x$ , its height above $O\,$ is $y$ .

Show that

\tan \theta - \frac{g x^2}{2 u^2 \cos^2 \theta}

Given that $θ=45∘\theta = 45^\circ$ and that when $x = 12$ , $y = 8$ , show that

6\sqrt{g}.

Hence find the speed of $P\,$ at the point where $x = 12$ and $y = 8$ .

Show that

\tan \theta - \frac{g x^2}{2 u^2 \cos^2 \theta}

Given that $θ=45∘\theta = 45^\circ$ and that when $x = 12$ , $y = 8$ , show that

6\sqrt{g}.

Hence find the speed of $P\,$ at the point where $x = 12$ and $y = 8$ .

Projectiles

Question 126

Markscheme

Projectiles

Question 126

Markscheme

Projectiles

Question 126

Projectiles Questions

Projectiles

Question 126

Projectiles Questions