A particle $P\,$ is projected from a point $O\,$ with velocity $Ums−1U\text{ms}^{-1}$ at an angle of $\theta^\circ\,$ to the horizontal. When $P\,$ has moved a horizontal distance $x$ , it's height above $O\,$ is $y$ .

Show that

\tan \theta - \frac{g x^2}{2U^2 \cos^2 \theta}

Given that $θ=45∘\theta = 45^\circ$ and that when $x = 8$ , $y = 6$ , find the speed of $P\,$ at the point where $x = 8$ and $y = 6$ .

Show that

\tan \theta - \frac{g x^2}{2U^2 \cos^2 \theta}

Given that $θ=45∘\theta = 45^\circ$ and that when $x = 8$ , $y = 6$ , find the speed of $P\,$ at the point where $x = 8$ and $y = 6$ .

Projectiles

Question 83

Markscheme

Projectiles

Question 83

Markscheme

Projectiles

Question 83

Projectiles Questions

Projectiles

Question 83

Projectiles Questions