The rational expression F(x)F(x)F(x) is defined by
F(x)=x2−1x2−4÷x+1x+2\displaystyle F(x)=\frac{x^2-1}{x^2-4}\div\frac{x+1}{x+2}F(x)=x2−4x2−1÷x+2x+1.
Simplify F(x)F(x)F(x), stating every excluded value of xxx.
Hence solve F(x)=3F(x)=3F(x)=3.