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3 Unit A2 1: Pure Mathematics (A-level only)

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Question 167

An arithmetic sequence has first term a a\,a and common difference ddd. The sum of the first 25 terms of the sequence is equal to the square of the sum of the first 10 terms.

a.

Show that 4a2+36ad+81d2=a+12d4a^2 + 36ad + 81d^2 = a + 12d4a2+36ad+81d2=a+12d.

[4]
b.

Given that the 10th term of the sequence is 2, find the possible values of aaa.

[4]
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3 Unit A2 1: Pure Mathematics (A-level only) Questions

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