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2.2 Kinematics

2.2 Kinematics

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Question 4

A particle moves with constant acceleration. Its velocity is (7i+j)(7\mathbf{i}+\mathbf{j})(7i+j) m s−1^{-1}−1 when t=2t=2t=2 s and (−i+9j)(-\mathbf{i}+9\mathbf{j})(−i+9j) m s−1^{-1}−1 when t=6t=6t=6 s. At time t=0t=0t=0, its position vector is (3i−4j)(3\mathbf{i}-4\mathbf{j})(3i−4j) m.

a.

Find the acceleration of the particle.

[2]
b.

Find its velocity when t=0t=0t=0.

[2]
c.

Find its position vector when t=5t=5t=5 s.

[2]
d.

Find the time at which the velocity is parallel to j\mathbf{j}j, and state the velocity at this time.

[2]
Markscheme

2.2 Kinematics Questions

  1. A Level
  2. /Maths
  3. /2.2 Kinematics

85 exam-style questions on CCEA A Level Maths 2.2 Kinematics, covering 2.2.1 Kinematics, 2.2.2 Kinematics, 2.2.3 Kinematics, and 2.2.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.

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