At time t=0t=0t=0, a particle has position vector (−4i+7j)(-4\mathbf{i}+7\mathbf{j})(−4i+7j) m, velocity (3i−5j)(3\mathbf{i}-5\mathbf{j})(3i−5j) m s−1^{-1}−1 and constant acceleration (1.5i+2j)(1.5\mathbf{i}+2\mathbf{j})(1.5i+2j) m s−2^{-2}−2.
Show that the particle has i\mathbf{i}i-component of position equal to 20 m when t=4t=4t=4 s.
Find the position vector of the particle when t=4t=4t=4.
Find the velocity of the particle when t=4t=4t=4.
85 exam-style questions on CCEA A Level Maths 2.2 Kinematics, covering 2.2.1 Kinematics, 2.2.2 Kinematics, 2.2.3 Kinematics, and 2.2.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.