Find the exact value of ∫244x2−3x+5(x−1)2(x+2)dx\displaystyle \int_2^4 \frac{4x^2 - 3x + 5}{(x-1)^2(x+2)} dx∫24(x−1)2(x+2)4x2−3x+5dx
363 exam-style questions on CCEA A Level Maths 3.6 Integration (A-level only), covering 3.6.1 Integration (A-level only), 3.6.2 Integration (A-level only), 3.6.3 Integration (A-level only), 3.6.4 Integration (A-level only), 3.6.5 Integration (A-level only), 3.6.6 Integration (A-level only), and 3.6.7 Integration (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.