Use the substitution u=6−exu = 6 - e^xu=6−ex to find ∫0ln2ex6−exdx\displaystyle \int_0^{\ln 2} \frac{e^x}{6 - e^x} dx∫0ln26−exexdx
363 exam-style questions on CCEA A Level Maths 3.6 Integration (A-level only), covering 3.6.1 Integration (A-level only), 3.6.2 Integration (A-level only), 3.6.3 Integration (A-level only), 3.6.4 Integration (A-level only), 3.6.5 Integration (A-level only), 3.6.6 Integration (A-level only), and 3.6.7 Integration (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.