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Differentiation

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Question 90

The point P P\,P lies on the curve with equation y=sec⁡(x2)\displaystyle y = \sec \left( \frac{x}{2} \right)y=sec(2x​) with x x\,x coordinate 2π3\displaystyle \frac{2\pi}{3}32π​.

Find an equation of the normal to the curve at the point PPP.

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Differentiation Questions

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