Solve, for −π<x<π-\pi < x < \pi−π<x<π, the equation
4cos(2x−0.3)+1=0 4\cos(2x - 0.3) + 1 = 0 4cos(2x−0.3)+1=0giving your answers, in radians, to 2 decimal places.
Solve, for 0∘<θ<360∘0^\circ < \theta < 360^\circ0∘<θ<360∘, the equation
3tanθsinθ=8−cosθ 3\tan \theta \sin \theta = 8 - \cos \theta 3tanθsinθ=8−cosθgiving your answers, in degrees, to one decimal place.