Skip to content
MathsGenie logo
Open app

Course home

  1. A Level
  2. Maths CCEA
  3. Question bank

Trigonometry and Modelling

EasyMediumHard
12345678
Question 6

The displacement ddd of a mechanical oscillator is modeled by the equation

d=0.9cos⁡(1.5t)−4.0sin⁡(1.5t) d = 0.9 \cos(1.5t) - 4.0 \sin(1.5t) d=0.9cos(1.5t)−4.0sin(1.5t)

where ddd is measured in millimetres and ttt is time in seconds. To analyze the peak amplitude of the oscillation, the expression is rewritten in the form Rcos⁡(1.5t+α)R \cos(1.5t + \alpha)Rcos(1.5t+α), where R>0R > 0R>0.

Find the value of RRR.

Circle the correct answer from the options below:

3.13.13.1 \qquad 4.054.054.05 \qquad 4.14.14.1 \qquad 4.94.94.9

[1]

Trigonometry and Modelling Questions

  1. A Level
  2. /Maths
  3. /Trigonometry and Modelling