Use the identity cos2θ+sin2θ=1\cos^2\theta + \sin^2\theta = 1cos2θ+sin2θ=1 to prove that tan2θ=sec2θ−1\tan^2\theta = \sec^2\theta - 1tan2θ=sec2θ−1
Solve, for 0≤θ≤3600 \leq \theta \leq 3600≤θ≤360, the equation,
tan2θ+sec2θ+5secθ=2 \tan^2\theta + \sec^2\theta + 5\sec\theta = 2 tan2θ+sec2θ+5secθ=2Give your answers to 1 decimal place.